Discover published sets by community

$\frac{x^2 - 4}{x^2 + 2x} - \frac{2}{x}$

$\left( \frac{2x}{x - 1} \right)^2 - \frac{4x^2}{x^2 - 2x + 1}$

$x\sqrt{x} - \frac{1}{2}x^{\frac{3}{2}}$

$\frac{3x}{x + 2} + \frac{2}{x + 2} - \frac{4x - 1}{x^2 + 4x + 4}$

$\frac{5}{x - 1} + \frac{3}{x + 1}$

$\frac{x}{x^2 - 4} - \frac{1}{x - 2}$

$\frac{2}{3x} + \frac{3}{2x} - \frac{5}{6x}$

$\frac{3x - 4}{x + 1} + \frac{1 - 2x}{x - 1}$

$1 - \left( \frac{x - 3}{x + 5} \right)$

$\frac{4}{5x} - \frac{3x} {25x^2}$

$\frac{x + 2}{x^2 - 3x - 4} - \frac{x - 3}{x^2 - x - 12}$

$\frac{x^2 - x - 6}{x^2 - 9} + \frac{2x + 3}{x + 3}$

$\left( \frac{2}{x} \right) \cdot \left( \frac{x^2}{2} \right)$

$\frac{2x + 1}{x - 3} - \frac{x + 4}{x + 3}$

$\frac{1}{x^2} - \frac{1}{x}$

$\frac{6}{x^2 - 4} + \frac{3}{x + 2}$

$\frac{x - 1}{x^2 - x} + \frac{2}{x}$

$\frac{x^2}{x - 1} - x - \frac{1}{x - 1}$

$\frac{x + 1}{x^2 + 2x + 1} - \frac{x - 1}{x + 1}$

$\frac{x - 2}{x^2 - 4} + \frac{3}{2 - x}$

$\frac{2(x + 1)}{x^2 - 1} - \frac{x + 1}{x - 1}$

$\left( \frac{1 - x}{x^2 + 2x} \right)$

$\frac{4x}{2 - x} - \frac{2x}{x - 2}$

$\frac{x^2 + x - 12}{x^2 - 4} + \frac{x - 2}{x + 2}$

$\frac{1}{x - 4} + \frac{2}{4 - x}$

$\frac{5}{x^2 - 25} - \frac{1}{5 - x}$

$\frac{4}{x + 3} - \frac{x}{x^2 - 9}$

$\frac{x + 5}{x^2 + 5x} + \frac{2}{x}$