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First-Order Linear Differential Equations

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Integrating factor of a first-order linear differential equation

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To solve the differential equation use the integrating factor μ(x)=eP(x)dx\mu(x) = e^{\int P(x) dx}, which transforms the equation into an exact differential.

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Nonhomogeneous first-order linear differential equation with constant coefficients

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For P(x)=pP(x) = p, a constant, the solution is y=1epx(epxQ(x)dx+C)y = \frac{1}{e^{px}}\left(\int e^{px}Q(x) dx + C\right).

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Standard form of a first-order linear differential equation

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The general solution is y=1μ(x)(μ(x)g(x)dx+C)y = \frac{1}{\mu(x)}\left(\int \mu(x)g(x) dx + C\right) where μ(x)\mu(x) is the integrating factor.

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Influence of initial conditions on the solution of a first-order linear differential equation

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Initial conditions allow for the determination of the constant of integration CC, thus providing the particular solution.

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Solving a first-order linear differential equation with variable separable after finding an integrating factor

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Once the integrating factor is applied, the resulting equation is separable, leading to a solution that can be expressed as an integral.

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Relationship between the integrating factor technique and the Laplace Transform method

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Both the integrating factor technique and the Laplace Transform method are used to solve linear differential equations, but Laplace Transforms are particularly useful for equations with discontinuous or impulsive forcing functions.

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Solution technique for exact equations derived from first-order linear differential equations

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Once a first-order linear differential equation is made exact using an integrating factor, the general solution can be found by integrating the exact equation.

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Application of linear differential equations to RC circuits

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The equation for charging an RC circuit, dqdt+1RCq=E\frac{dq}{dt} + \frac{1}{RC}q = E, can be solved using an integrating factor, yielding the charge q(t)q(t) at any time tt.

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General solution of homogeneous first-order linear differential equation

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For Q(x)=0Q(x) = 0, the general solution is y=CeP(x)dxy = Ce^{-\int P(x) dx}, where CC is the constant of integration.

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Behavior of the solution to a first-order linear differential equation as xx \to \infty

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If P(x)P(x) is positive and bounded away from zero, the solution y=1μ(x)(μ(x)g(x)dx+C)y = \frac{1}{\mu(x)}\left(\int \mu(x)g(x) dx + C\right) typically approaches zero as xx \to \infty.

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